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Harris Park vs Peakhurst

Property investment comparison - Harris Park, NSW 2150 vs Peakhurst, NSW 2210

Head-to-head across core investment metrics: Harris Park wins 3, Peakhurst wins 2. The better choice depends on whether you're optimising for cash flow, growth, affordability, or liquidity, the table below highlights the winner on each metric.

MetricHarris ParkPeakhurst
Median house price$1.7M$1.7M
Median unit price$510K$835K
Gross rental yield (houses)-2.66%
Gross rental yield (units)6.11%4.60%
1-year house growth+6.5%estimate+3.4%estimate
3-year house growth--
Vacancy rate2.0%1.0%
Population5,04312,079

Harris Park vs Peakhurst: what the numbers say

The median house price is $1.7M in Harris Park and $1.7M in Peakhurst, so Peakhurst is the cheaper entry point.

For units, Harris Park sits at a median of $510K against $835K in Peakhurst, which makes Harris Park the more affordable unit market and Peakhurst the pricier one.

Over the past year house prices moved +6.5% in Harris Park (an estimate) and +3.4% in Peakhurst (an estimate), so recent momentum favours Harris Park, although both suburbs recorded growth.

Rental vacancy is 1.0% in Peakhurst and 2.0% in Harris Park, so landlords in Peakhurst face less competition for tenants. Anything under 2% is generally read as a tight market where tenants compete for homes.

Peakhurst is the bigger suburb, with a population of 12,079 against 5,043, roughly 2.4 times the size of Harris Park; a larger suburb usually means a deeper pool of buyers and tenants.

In short: Peakhurst for a lower purchase price, Harris Park for recent price momentum, Peakhurst for the tighter rental market. Which matters more depends on whether the investor is buying for cash flow, capital growth or affordability.

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