Lindendale vs Robertson
Property investment comparison - Lindendale, NSW 2480 vs Robertson, NSW 2577
Head-to-head across core investment metrics: Lindendale wins 3, Robertson wins 1. The better choice depends on whether you're optimising for cash flow, growth, affordability, or liquidity, the table below highlights the winner on each metric.
| Metric | Lindendale | Robertson |
|---|---|---|
| Median house price | $1.2M | $1.2M |
| Median unit price | $450K | $645K |
| Gross rental yield (houses) | - | 3.20% |
| Gross rental yield (units) | 5.18% | 5.56% |
| 1-year house growth | - | +1.1% |
| 3-year house growth | - | +2.4% |
| Vacancy rate | 0.5% | 3.4% |
| Population | 263 | 2,017 |
Lindendale vs Robertson: what the numbers say
The median house price is $1.2M in Lindendale and $1.2M in Robertson, so Lindendale is the cheaper entry point.
For units, Lindendale sits at a median of $450K against $645K in Robertson, which makes Lindendale the more affordable unit market and Robertson the pricier one.
Rental vacancy is 0.5% in Lindendale and 3.4% in Robertson, so landlords in Lindendale face less competition for tenants. Anything under 2% is generally read as a tight market where tenants compete for homes.
Robertson is the bigger suburb, with a population of 2,017 against 263, roughly 8 times the size of Lindendale; a larger suburb usually means a deeper pool of buyers and tenants.
In short: Lindendale for a lower purchase price, Lindendale for the tighter rental market. Which matters more depends on whether the investor is buying for cash flow, capital growth or affordability.
Keep exploring
- National investment guide - top suburbs across every metric
- Take the suburb finder quiz - 5 questions to match your goals
- How our investment score works
- Property investment glossary - every term defined
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