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San Remo vs Tanilba Bay

Property investment comparison - San Remo, NSW 2262 vs Tanilba Bay, NSW 2319

Head-to-head across core investment metrics: San Remo wins 4, Tanilba Bay wins 1. The better choice depends on whether you're optimising for cash flow, growth, affordability, or liquidity, the table below highlights the winner on each metric.

MetricSan RemoTanilba Bay
Median house price$810K$815K
Median unit price--
Gross rental yield (houses)-4.02%
Gross rental yield (units)3.74%3.95%
1-year house growth+8.7%+5.3%
3-year house growth+23.7%+9.1%
Vacancy rate0.6%1.3%
Population4,4343,237

San Remo vs Tanilba Bay: what the numbers say

The median house price is $810K in San Remo and $815K in Tanilba Bay, so San Remo is the cheaper entry point, with Tanilba Bay houses about 1% dearer.

Over the past year house prices moved +8.7% in San Remo and +5.3% in Tanilba Bay, so recent momentum favours San Remo, although both suburbs recorded growth.

Looking back three years, San Remo houses are +23.7% and Tanilba Bay houses +9.1%, so San Remo has compounded faster than Tanilba Bay over the longer window.

Rental vacancy is 0.6% in San Remo and 1.3% in Tanilba Bay, so landlords in San Remo face less competition for tenants. Anything under 2% is generally read as a tight market where tenants compete for homes.

San Remo is the bigger suburb, with a population of 4,434 against 3,237, larger than Tanilba Bay; a larger suburb usually means a deeper pool of buyers and tenants.

In short: San Remo for a lower purchase price, San Remo for recent price momentum, San Remo for the tighter rental market. Which matters more depends on whether the investor is buying for cash flow, capital growth or affordability.

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