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St Albans Park vs Strzelecki

Property investment comparison - St Albans Park, VIC 3219 vs Strzelecki, VIC 3950

Head-to-head across core investment metrics: St Albans Park wins 1, Strzelecki wins 3. The better choice depends on whether you're optimising for cash flow, growth, affordability, or liquidity, the table below highlights the winner on each metric.

MetricSt Albans ParkStrzelecki
Median house price$700K$705K
Median unit price$490K$255K
Gross rental yield (houses)3.89%4.25%
Gross rental yield (units)4.20%-
1-year house growth+13.1%-
3-year house growth+19.8%-
Vacancy rate0.9%0.5%
Population4,942107

St Albans Park vs Strzelecki: what the numbers say

The median house price is $700K in St Albans Park and $705K in Strzelecki, so St Albans Park is the cheaper entry point, with Strzelecki houses about 1% dearer.

For units, St Albans Park sits at a median of $490K against $255K in Strzelecki, which makes Strzelecki the more affordable unit market and St Albans Park the pricier one.

On cash flow, Strzelecki leads: houses there return a gross rental yield of 4.25%, compared with 3.89% in St Albans Park, a gap of 0.36 percentage points.

Rental vacancy is 0.5% in Strzelecki and 0.9% in St Albans Park, so landlords in Strzelecki face less competition for tenants. Anything under 2% is generally read as a tight market where tenants compete for homes.

St Albans Park is the bigger suburb, with a population of 4,942 against 107, roughly 46 times the size of Strzelecki; a larger suburb usually means a deeper pool of buyers and tenants.

In short: Strzelecki for rental income, St Albans Park for a lower purchase price, Strzelecki for the tighter rental market. Which matters more depends on whether the investor is buying for cash flow, capital growth or affordability.

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